3x²+4x+1 = u
du = (6x+4)dx
dx = du/(6x+4)
= du/2(3x+2)
= 1/2 . ∫ (x dari 0 sampai 1)
= 1/2 , ∫1/u² . du
= 1/2 . (-1) [ 1/u] (x dari 0 sampai 1)
= -1/2 (1/(3.1²+4.1+1) - 1/(3.0²+4.0+1))
= -1/2 (1/8 - 1)
= -1/2 (-7/8)
= 7/16
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3x²+4x+1 = u
du = (6x+4)dx
dx = du/(6x+4)
= du/2(3x+2)
= 1/2 . ∫
(x dari 0 sampai 1)
= 1/2 , ∫1/u² . du
= 1/2 . (-1) [ 1/u] (x dari 0 sampai 1)
= -1/2 (1/(3.1²+4.1+1) - 1/(3.0²+4.0+1))
= -1/2 (1/8 - 1)
= -1/2 (-7/8)
= 7/16