Jawab:
Limit bentu 0/0
Penjelasan dengan langkah-langkah:
lim(x-> - 3 ) { x² - 9 } / { 3 - √(2x + 15)}
= lim (x-> -3) { (2x)(3 + √(2x +15) } / (-2)
= lim(x-> -3) (-x)(3 + √(2x + 15)
x= - 3 --> - (-3) (3 + 3) = 3 (6) = 18
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Jawab:
Limit bentu 0/0
Penjelasan dengan langkah-langkah:
lim(x-> - 3 ) { x² - 9 } / { 3 - √(2x + 15)}
= lim (x-> -3) { (2x)(3 + √(2x +15) } / (-2)
= lim(x-> -3) (-x)(3 + √(2x + 15)
x= - 3 --> - (-3) (3 + 3) = 3 (6) = 18