Question

Tolong bantuannya nomer 14 ya...

Answer 1

Diket :
ΔH = - 109 kJ/mol
C=O, H-O, O=O berturut 243, 432, 335 kJ/mol
ditanya :
C-H = ......?
jawab :
ΔH = {(Σei kiri) - (Σei kanan)}
ΔH = {(4.C-H + 2.O=O) - (2.C=O + 4.H-O)
- 109 = {(4.C-H + 2 . 335) - (2 . 243 + 4 . 432)
- 109 = ({4C-H + 670) - (486 + 1728)
- 109 = 4C-H + 670 - 2214
- 109 = 4C-H - 1544
- 109 + 1544 = 4C-H
C-H = 1435 / 4
C-H = 358,75 kJ/mol