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3^R=3
R=1
(0,9/0,3)^Q=6/6
3^Q=1
Q=0
(0,2/0,6)^P x (0,2/0,3)^Q x (0,9/0,3)^R = 6/6
(1/3)^P=1/3
P=1
jawaban c. v=k[P][R]