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y=x^4-2x^2
nilai minimum ={ -2 =< x =< 2 }
Turunan 1:
y'=4x^3-4x
f(-2)=4x^3-4x
=4(-2)^3-4(-2)
=4(-8)+8
=-32+8
=-24
f(-1)=4(-1)^3-4(-1)
=4(-1)+4
=-4+4
=0
f(0)=4(0)^3-4(0)
=4(0)-0
=0
f(1)=4(1)^3-4(1)
=4(1)-4
=4-4
=0
f(2)=4(2)^3-4(2)
=4(8)-8
=32-8
=24
Pilihan A.x=-2 menghasilkan y=-24 (paling minimum).
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