" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
y' = 3x^2 + 12x +9
y" = 6x +12
mempunyai titik belok apabila y" = 0
maka 6x + 12 = 0
6x = -12
x = -2
jika y = f(x) maka
f(-2) = (-2)^3 + 6(-2)^2 + 9(-2) + 7
f (-2) = -8 + 24 - 18 +7
f(-2) = 5
jadi titik beloknya adalah (-2,5)