(1+cos alfa)[1/sin alfa+1/tg alfa]=sin alfa Prosze o pomoc :(
po konsultacji z nadawca zostal wykryty blad,miedzy 1/sin i 1/tg jest minu s a ni eplus
(1+cos)(1/sin-1/tg)=sin
(1+cos)(1/sin-1/sin/cos)=sin
1+cos(1/sin-cos/sin)=sin
(1+cos)/sin-(cos+cos²)/sin=sin
(1+cos-cos-cos²)/sin=sin
(1-cos²)/sin=sin
sin²/sin=sin
sin=sin
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
po konsultacji z nadawca zostal wykryty blad,miedzy 1/sin i 1/tg jest minu s a ni eplus
(1+cos)(1/sin-1/tg)=sin
(1+cos)(1/sin-1/sin/cos)=sin
1+cos(1/sin-cos/sin)=sin
(1+cos)/sin-(cos+cos²)/sin=sin
(1+cos-cos-cos²)/sin=sin
(1-cos²)/sin=sin
sin²/sin=sin
sin=sin