Question

Tentukan y' dari:
a. y = ∛x²
b. y = √4x - 3
c. y = ( x - 2 ) ( 3x + 1 )min²

Answer 1

A. y = x²/³
y' = ²/₃ x⁻⁽¹/³⁾
y' = 2/(3∛x)

b. y = √(4x-3) = (4x-3)¹/²
y' = 1/2 (4x-3)⁻¹/² (4)
y'  = 2 (4x -3)⁻¹/²
y' = 2/(√(4x-3))

c. y = (x-2)/(3x+1)² ....y = u v
y' = (u'v - uv')/(v²)
y' = {1(3x+1)² - (x-2)(2)(3x+1)}  / (3x+1)⁴
y' = { (3x+1)² -(2x-4)(3x+1)} / (3x+1)⁴
y' = (3x+1)(3x+1 - 2x+4) /(3x+1)⁴
y' = (x+5)/(3x+1)³