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2x + y = 4
2x + 3y = 6
----------------- _
-2y = -2
y = 1
2x + 1 = 4
2x = 3
x = 3/2
titik (2,0) ---> f(2,0) = 2(2) + 3(0) = 4
titik (3/2,1) -> f(3/2,1) = 2(3/2) + 3(1) = 6
titik (0,2) ---> f(0,2) = 2(0) + 3(2) = 6
nilai maks 6