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Kb = 10^-5
M (NH4)2SO4 = 0,1 M
Val (NH4)2SO4 = 2
Ph = 9
Perbandingan volume?
PH = 14 - POH
POH = 14 - PH
POH = 14 - 9
POH = 5
POH = -log [OH-]
5 = -log [OH-]
-log 10^-5 = -log [OH-]
[OH-] = 10^-5
[OH-] = kb . mol basa/val. mol garam
[OH-] = kb . M.V basa / val.M.V garam
10^-5 = 10^-5 . 2. 10^-1 .V basa/ 2 . 10^-1 . V garam
V basa/V garam = 1/1
V NH4OH : V (NH4)2SO4 1 : 1