Question

Tentukan penyelesaian dari persamaan eksponen berikut!
a. 3^x-2 = 12
b. 2^2x+1 = 5^x-2

Answer 1

A)
3^(x-2) = 12
3^x . 3^-2 = 12
3^x= 3^2. 3.2^2.  
x = 3'log 3^3. 2^2
x = 3 + 2. 3'log 2
.
b)
2^(2x+1) = 5^(x-2)
2^2x .2 = 5^x . 5^-2
4^x. (2) (5^2) = 5^x
(50), 4^x = 5^x
log 50 + log 4^x = log 5^x
log 50 + x . log 4 = x log 5
log 50 = x loh 5 - x log 4
log 50 = x (log 5 - log 4)
x = log 50 / (log 5 -log 4)
x = (log 10+log 5)/(log 5 - log 4)
x = (1 + 0,699)/ (0,699 - 0,602)
x = 1,699 / 0,097
x = 17,3
"koreksi"

Answer 2

Selesaikan dengan logaritma:
a.)


b.)