Question

Temat: Mnożenie sum algebraicznych .

(x+3) (3y-1) =

(3b+1) (2+3a)=

(5x-2) (2y-3)=

(2x-y) ( 4x+3y)=

(3x+y) (2x-3y)=

(0,2a-b) (b-10a)=

Answer 1

(x+3)(3y-1)=3xy+x+9y-3

(3b+1)(2+3a)=6b+9ab+2+3a

(5x-2)(2y-3)=10xy-15x-4y+6

(2x-y)(4x+3y)=8x^2+6xy-4xy-3y^2=8x^2+2xy-3y^2            (x^2= z do kwadratu)

(3x+y)(2x-3y)=6x^2-9xy+2xy-3y^2=6x^2-7xy-3y^2

(0,2a-b)(b-10a)=0,2ab-2a^2-b^2+10ab

Answer 2

(x+3)(3y-1)= 3xy-x+9y-3

(3b+1)(2+3a)=6b+9ab+2+3a

(5x-2)(2y-3)=10xy-15x-4y+6

(2x-y)(4x+3y)=8x kwadrat+6xy-4xy-3y kwadrat=8x kwadrat +2xy-3y kwadrat

(3x+y)(2x-3y)=6x kwadrat-9xy+2xy-3y kwadrat=6x kwadrat -7xy-3y kwadrat

(0,2a-b)(b-10a)=0,2ab-2a kwadrat -b kwadrat +10ab=10,2ab-2a kwadrat-b kwadrat