takie 2 zadania z chemii
1.Oblicz stężenie jonów H3O+ w roztworach o a)pH = 9,33; b) pH=0.01; c) pH=2.
2.Oblicz pH 0,1M CH3COOH. Stopień dysocjacji α=5%.
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1.
a) pH-log[H+]
9,33=-log[H+]
[H+]=4,67 *10^-10
b) pH-log[H+]
0,01=-log[H+]
[H+]=0,97
c) pH-log[H+]
2=-log[H+]
[H+]=10^-2
Zad 2
C=0,1M
α=5%