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b=3√2
c=4√3
pole=2ab+2ac+2bc=2×2√3×3√2+2×2×4√3+2×3√2×4√3=
12√6+16√3+24√6=36√6+16√3=4(9√6+4√3)cm²
Odp. Pole powierzchni prostopadłościanu wynosi 12(3√6+4) [j²].