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k-ilosc sukcesów
X=1
p=1/6 q=5/6 n=10 k=1
P(1)=10·1/6·(5/6)⁹=5/3·(5/6)⁹= 0,323
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X' - brak sukcesow - ani raz nie wypadnie szóstka
p=1/6 q=5/6 n=10 k=0
P(0)=1·(1/6)⁰·(5/6)¹⁰=0,162
P(X)=1-(5/6)¹⁰= 0,838