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[OH-]= 5x10^-4
[OH-]=(akar) Kb [LOH]
[OH-]^2=Kb[LOH]
(5x10^-2)^2= 2,5x10^-5 [LOH]
[LOH]= 2,5x10^-3/2,5x10^-5
[LOH]=10^-8
jd konsentrasi basa tersebut (LOH) adalah 10^-8