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n= 0,74/74
= 0,01 mol
B. M= n/ V
M= 0,01 mol/0,5 L
= 0,02 M
C. Reaksi ionisasi Ca(OH)2:
Ca(OH)2 --> Ca2+ + 2OH-
0,02 0,02 0,04
Nah, ambil 0,04 karena:
pOH= -log[OH-]
= -log[4x10^-2]
= 2-log4
pH= 12+log 4 (E)
*Terbaik dan bintang 5 ya kalau bisa :)