December 2018 0 7 Report
Sprawdzicie ??
 \lim_{n \to \ -1} \frac{x^2+2x+1}{x^2-1}= \frac{(x+1)^2}{(x-1)(x+1)} = \frac{x+1}{x-1} = \frac{0}{-2} = 0


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