Sporzadź tabele funkcji
h(x)= x+1 pod spodem x-1
h(x)=(x+1)/(x-1) x≠1
f(-2)=(-2+1)/(-2-1)=1/3
f(-1)=(-1+1)/(-1-1)=0
f(-1/2)=(-1/2+1)/(-1/2-1)=1/2*(-2/3)=-1/3
f(0)=(0+1)/(0-1)=-1
f(1/2)=3/2 : (-1/2)=3/2 *(-2)=-3
f(2)=(2+1)/(2-1)=3/1=3
x -2 -1 -1/2 0 1/2 2
y 1/3 0 -1/3 -1 -3 3
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h(x)=(x+1)/(x-1) x≠1
f(-2)=(-2+1)/(-2-1)=1/3
f(-1)=(-1+1)/(-1-1)=0
f(-1/2)=(-1/2+1)/(-1/2-1)=1/2*(-2/3)=-1/3
f(0)=(0+1)/(0-1)=-1
f(1/2)=3/2 : (-1/2)=3/2 *(-2)=-3
f(2)=(2+1)/(2-1)=3/1=3
x -2 -1 -1/2 0 1/2 2
y 1/3 0 -1/3 -1 -3 3