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⇔ ∫ [4x - 3][6x - 4x²]^(- 2/3) dx
⇔ u = 6x - 4x²
⇔ du/dx = 6 - 8x
⇔ dx = du / [6 - 8x]
⇔ ∫ [4x - 3].u^(- 2/3) du / [6 - 8x]
⇔ ∫ [4x - 3].u^(- 2/3) du / [- 2(4x - 3)]
⇔ - ½ ∫ u^(- 2/3) du
⇔ - ½ .3.u^(1/3) + c
∴ ∫ [4x - 3][6x - 4x²]^(- 2/3) dx = - 3/2.∛[6x - 4x²] + c
[2]. pembahasan pada gambar terlampir