Question

Skroc ulamki
-2(x+1)^2+2x+2 podzielic przez 2x^2 - 2x

Answer 1

[-2(x+1)²+2x+2] / (2x²-2x)=[-2(x²+2x+1)+2x+2] /(2x²-2x)=

(-2x²-4x-2+2x+2) / (2x²-2x)= (-2x²-2x) /(2x²-2x)=[-2x(x+1) ]/[-2x(1-x)]=(x+1)/(1-x)

Przy zalozeniu
2x²-2x≠0
2x(x-1)≠0 ⇔2x≠0 ∧ x-1≠0
                     x≠0 ∧ x≠1

Answer 2

-2(x+1)2+2x+2/2x2-2x = -2(x2+2x+1)+2x+2/-2x2-2x = -2x2-4x-4+2x+2/-2x2-2x = -2x2-2x/2x2-2x = = 1