skonstruuj odcinek o długości na dwa różne sposoby. .
zapisz krócej :
z.1
2^2 + 3^2 = 4 + 9 =13
Rysujemy trójkąt prostokątny o przyprostokatnych:
a = 2, b = 3
Wtedy c = p(13)
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z.2)
p(2)* [ p(5) + 2 p(5)] = p(10) + 2 p(10) = 3 p(10)
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p3st(15) * [ 2 p3s5(15)]^2 =
= 15^(1/3) * 4* [ 15^(1/2)]^2 = 4* 15^(1/3)*15^(2/3) = 4* 15^1 = 60
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z.1
2^2 + 3^2 = 4 + 9 =13
Rysujemy trójkąt prostokątny o przyprostokatnych:
a = 2, b = 3
Wtedy c = p(13)
==============
z.2)
p(2)* [ p(5) + 2 p(5)] = p(10) + 2 p(10) = 3 p(10)
=============================================
p3st(15) * [ 2 p3s5(15)]^2 =
= 15^(1/3) * 4* [ 15^(1/2)]^2 = 4* 15^(1/3)*15^(2/3) = 4* 15^1 = 60
============================================================