Sistema de ecuaciones con dos incógnitas- metodo de reducción
x = 2(y+1)
y = 3(x-2)
x = 2(y+1)
y = 3(x-2)
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-3x+y=-6....(2). //x2
x-2y=2
-6x+2y=-12
-5x=-10
X= - 10/-5
X=2
Reemplazamos en 2
Y=3(2-2)
Y=0