Question

Sin²x - cos x = 1, 0 < x < 180
Maka sin x = ?

Tolong dibantu ya

Answer 1

Answer 2

Sin^2 = 1-cos^2
1-cos^2 x - cos x = 1
-cos^2 x - cos x = 0
cos^2 x + cos x = 0
cos x(cos x + 1)=0
cos x = 0
sin(90-x) = 0
sin (90-x)= sin 0| 90-x = 0 | -x=-90 | x=90°
sin (90-x) = -1
sin (90-x) = sin 270 | 90-x = 270 | -x = 180 | x = - 180(salah)
berarti x = 90°
sin 90 = 1