sin² 60° + 3 tg 30° razy cos 30°
------------------------------------- =
1-3 tg 45°
[ sin ^2 (60 st) + 3 tg 30 st * cos 30 st ]/ [ 1 - 3 tg 45 st ] =
= [ ( p(3)/2)^2 + 3*p(3)/3 * (p(3)/2)] /[ 1 -3*1 ] =
= [ 3/4 + 3/2 ] / ( -2) = [ 3/4 + 6/4 ] / ( - 2) =
= ( 9/4) / (-2) = - 9/8
============================
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
[ sin ^2 (60 st) + 3 tg 30 st * cos 30 st ]/ [ 1 - 3 tg 45 st ] =
= [ ( p(3)/2)^2 + 3*p(3)/3 * (p(3)/2)] /[ 1 -3*1 ] =
= [ 3/4 + 3/2 ] / ( -2) = [ 3/4 + 6/4 ] / ( - 2) =
= ( 9/4) / (-2) = - 9/8
============================