Dt = 120 ºF – 70 ºF = 50 ºF
ºC = 50 (5/9)
ºC = 27.77
1 K = ºC
LA VARIACIÓN ES:
ΔT = 27.8 K
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Dt = 120 ºF – 70 ºF = 50 ºF
ºC = 50 (5/9)
ºC = 27.77
1 K = ºC
LA VARIACIÓN ES:
ΔT = 27.8 K