Question

Buktikan Bahwa Sec²∅+Cosec²∅/sec∅.cosec∅=Tan∅+Cot∅​

Answer 1

berarti :

(1/cos² α + 1/sin²a) / (1/cos α.1/sin α) =

((sin² α + cos² α) / (sin² α cos² α )) / (1/cos .α sin α ) =

((sin² α + cos² α ) (cos α sin α )) / (sin² α cos² α ) =

(sin² α + cos² α) / sin a cos a =

(sin α / cos α ) + (cos α / sin α) =

tan α + cot α

Answer 2

(sec²∅ + cosec²∅) / (sec∅ . cosec∅)

= (1/cos²∅ + 1/sin²∅) / (1/cos∅ . 1/sin∅)

= ((sin²∅ + cos²∅)/(cos²∅.sin²∅)) / (1/cos∅.sin∅)

= ((sin²∅ + cos²∅)/(cos²∅.sin²∅)) x cos∅. sin∅

= ((sin²∅ + cos²∅)/(cos ∅.sin ∅))

= (sin²∅ / cos∅. sin∅) + (cos²∅ / cos∅. sin∅)

= sin∅/cos∅ + cos∅/sin∅

= tan∅ + cot∅