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Verified answer
Mata Pelajaran : KimiaMateri : Stokiometri
x (jmlh molekul) = 3,01 × 10²² molekul
m (massa) = 8 gram
Ar A = 20
Ar B = ?
l (bilangan Avogrado) = 6,02 × 10²³ molekul/mol
n = x/l
Mr A2B3 = m/n
= 8/0,05 = 160 gram/mol
Mr A2B3 = 2(Ar A) + 3(Ar B)
160 = 2(20) + 3(Ar B)
160 = 40 + 3Ar B
160 - 40 = 3Ar B
120 = 3Ar B
Ar B = 120/3 = 40 (B)
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