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2B 3C 1Z razem 6
obliczamy prawdopodobieństwo wylosowania dwóch takich samych:
2 białe lub 2 czarne lub 2 zielone:
P(A) = 4/9 * 2/6 + 3/9 * 3/6 + 2/9 * 1/6 = 4/27 + 1/6 + 1/27 = 19/54