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t=0,5 h = 1800 sek
s=vt=1,2*1800 = 2160 m
t = 0,5h = 1800s
S= v*t
s= 1800s*1,2 m/s = 2160
Odp. Piechur przebędzie drogę 2160 m
t= 0,5h.= 1800s
s=?
v=s/t|t
s=v*t
s=1.2m/s*1800s
s=2160m