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|Ω|=6*6=36
|AnB|=36-6=30 (bez (1,1)(2,2)(3,3)(4,4)(5,5)(6,6))
P(AnB)=30/36 = 5/6
P(B) = 30/36 = 5/6
P(A/B)=P(AnB)/P(B)=5/6 : 5/6 = 1 zdarzenie pewne