rozwiązać:
2x²+x+2x-x²-x=-1
2x² +x+2x-x²-x=-1 x²+2x+1=0Δ=0x = -b/2a = -2/2 = -1
2x² - x² + 2x = -1
x² + 2x + 1 = 0
delta = b² - 4ac = 2² - 4*1*1 = 4 - 4 = 0
x0 = -b/2a = -2/2*1 = -2/2 = -1
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2x² +x+2x-x²-x=-1
x²+2x+1=0
Δ=0
x = -b/2a = -2/2 = -1
2x²+x+2x-x²-x=-1
2x² - x² + 2x = -1
x² + 2x + 1 = 0
delta = b² - 4ac = 2² - 4*1*1 = 4 - 4 = 0
x0 = -b/2a = -2/2*1 = -2/2 = -1