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3(x+3)+2y=3
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2x + 5y=2
3x +9 + 2y=3
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2x+ 5y=2
3x + 6 +2y
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2x + 5y=2
3x=-6 - 2y /:3
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2x+ 5y =2
x= -2 -2/3
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2* (-2 - 2/3) + 5y =2
-4 - 1 1/3 +5y=2
5y= 4 + 1 1/3 + 2
5y= 7 1/3 //:5
y= 1 7/15 nie wiem czy dobrze ;] a tamtego nie mogę sobie wyobrazic gdzie ta kreska ulamkowa