Rozwiąz równanie:
2x-=2+x
Rozwiąż nierowność
(x+4)^2+(x+1)^2-4(1-x)
2x - 3√2 = 2 + √2x
2x - √2x = 2 + 3√2
x( 2-√2) = 2 + 3√2 /:(2-√2)
x = (2+3√2)/(2-√2) * (2+√2)/(2+√2)
x= (4+2√2+6√2+6)/(4-2)
x=(10+8√2)/2
x= 5+4√2
x²+8x+16+x²+2x+1 ≥ -4 + 4x
2x²+6x +21 ≥ 0
Δ=b²-4ac=36 - 168 = - 132
brak pierwiastków
x∈R
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
2x - 3√2 = 2 + √2x
2x - √2x = 2 + 3√2
x( 2-√2) = 2 + 3√2 /:(2-√2)
x = (2+3√2)/(2-√2) * (2+√2)/(2+√2)
x= (4+2√2+6√2+6)/(4-2)
x=(10+8√2)/2
x= 5+4√2
x²+8x+16+x²+2x+1 ≥ -4 + 4x
2x²+6x +21 ≥ 0
Δ=b²-4ac=36 - 168 = - 132
brak pierwiastków
x∈R