February 2019 0 42 Report
Wykaż, że dla dowolnych liczb nieujemnych a i b prawdziwa jest nierówność:
 a)a+b \geq 4 \sqrt{ab} \\ \\ b) a+ \frac{b}{2} \geq \sqrt{2ab} \\ c)\sqrt{a} ( \frac{1}{2} \sqrt{b} - \sqrt{a}) \leq \frac{b}{16}}
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