Rozwiaz rownanie:
x^2(x-3)+2x(x-3)+x-3=0
z gory dzieki
x²(x-3)+2x(x-3)+1(x-3)=0
(x²+2x+1)(x-3)=0
(x+1)(x+1)(x-3)=0
x+1=0 lub x-3=0
x=-1 lub x=3
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x²(x-3)+2x(x-3)+1(x-3)=0
(x²+2x+1)(x-3)=0
(x+1)(x+1)(x-3)=0
x+1=0 lub x-3=0
x=-1 lub x=3