Question

(3z-2)2=9(z-2)(z+3)

Answer 1

9z²-12z+4=9(z²+3z-2z-6)

9z²+27z-18z-54-9z²+12z-4=0

21z=58

z=58/21=2 i 16/21

Answer 2

6z-4=9(z²+3z-2z-6) <=> 6z-4 = 9z²+9z-6 <=> 9z²-3z-2 = 0  

 

Δ= 9+ 72 = 81, √Δ= 9

 

Z1 = -b-√Δ/2a = -6\ 18 = -1/3

Z2 = -b+√Δ/2a = 12/18 = 2/3 

 

Z ∈ { -1/3,2/3}