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x^3-3x^2+2x-6=0 ^ x^3+3x^2+2x+6=0
x^2(x-3)2(x-3)=0 ^ x^2(x+3)2(x+3)=0
(x^2+2)(x-3)=0 ^ (x^2+2)(x+3)=0
x=3 ^ x=-3
D=R-{-3,3}
Rozwiązywanie:
7(x^3+3x^2+2x+6)=4(x^3-3x^2+2x-6)
7x^3+21x^2+14x+42-4x^3+12x^2-8x+24=0
3x^3+33x^2+6x+66=0
3x^2(x+11)6(x+11)=0
x=-11