Rozwiaz rownanie wymierne;
(x-3) (1-x)=(2x-1)(x-3)
x-x^-3+3x-= 2x^-6x-x+3 ^- do kwadratu
-3x^+11x=0
delta= 121
pierwiastek z 121 to 11
x1= -b - delta \ 2a x1= 3,6
x2 = -b +delta \2x x2= 0
(x-3)(1-x)=(2x-1)(x-3)
x-x^2-3+3x=2x^2-6x-x+3
-x^2+11x=0
-x^2=-11x
x^2=11x /x
x=11
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
x-x^-3+3x-= 2x^-6x-x+3 ^- do kwadratu
-3x^+11x=0
delta= 121
pierwiastek z 121 to 11
x1= -b - delta \ 2a x1= 3,6
x2 = -b +delta \2x x2= 0
(x-3)(1-x)=(2x-1)(x-3)
x-x^2-3+3x=2x^2-6x-x+3
-x^2+11x=0
-x^2=-11x
x^2=11x /x
x=11