rozwiaz ponizsze uklady metoda przeciwnnych wspolczynnikow:
a) {2x+7y=16
{4x+3y=10
b) {5x+2y=20
{7x+3y=29 klamry powinny byc duze
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a) { 2x+ 7y =16 / ( * (-2)
{ 4x+ 3y= 10
{ -4x -14y= -32
{ 4x+ 3y = 10
-11 y = -22 / :(-11)
y= 2
4x+3*2 =10
4x+ 6=10
4x=4 /4
{x=1
{y=2
b) { 5x+ 2y =20 / * (-3)
{ 7x+ 3y= 29 / *2
{-15x- 6y= -60
{14x + 6y= 58
-x = -2 / : (-1)
x= 2
5*2 + 2y= 20
10 + 2y = 20
2y= 10 / :2
{y=5
{x=2
Proszę ;-) Liczę na naj ;P
a)
{2x+7y=16 /·(-2)
{4x+3y=10
{-4x-14y=-32
{4x+3y=10
______________
-14y+3y=-32+10
-11y=-22 /:(-11)
y=2
{4x+3·2=10
{4x=10-6
{4x=4 /;4
{x=1
{y=2
{x=1
b)
{5x+2y=20 /·(-1,5)
{7x+3y=29
{-7,5x-3y=-30
{7x+3y=29
_______________
-7,5x+7x=-30+29
-0,5x=-1 /;0,5
x=2
{5·2+2y=20
{10+2y=20
{2y=20-10
{2y=10 /;2
{y=5
{x=2
[y=5