Question

Rozwiąż
a)
b)

Answer 1

a)

(x³-2x²-5x+6):(x-1)=x²-x-6

-x³+x²

------------

     -x²-5x

      x²-x

--------------

         -6x+6

          6x-6

         =====

(x-1)(x²-x-6)=0

(x-1)(x²+2x-3x-6)=0

(x-1)[x(x+2)-3(x+2)]=0

(x-1)(x+2)(x-3)=0

x∈{-2, 1, 3}

b)

x²(x+3)-5(x+3)≤0

(x+3)(x²-5)≤0

(x+3)(x+√5)(x-√5)≤0

x∈(-∞,-3> u <-√5, √5>

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