Rozwiąż:
a) (1-2x)do kwadratu = 2x-x do kwadratu + 1
b) 3x do kwadratu - x - 2 > 0
Z góry dzieki :)
1-4x+4x²-2x+x²-1=0
5x²-6x=0
x(5x-6)=0
x=0 x=6/5
b) 3x² - x - 2 > 0
Δ=1+24=25 √Δ=5 x₁=5+1/6=1 x₂=-5+1/6=-2/3
x∈(-∞,-2/3)∨(1,+∞)
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a) (1-2x)do kwadratu = 2x-x do kwadratu + 1
1-4x+4x²-2x+x²-1=0
5x²-6x=0
x(5x-6)=0
x=0 x=6/5
b) 3x² - x - 2 > 0
Δ=1+24=25 √Δ=5 x₁=5+1/6=1 x₂=-5+1/6=-2/3
x∈(-∞,-2/3)∨(1,+∞)