Rozwiąż.
(100x+10y+z) = 365+(100y+10x+z+5)
Pod Y podstawiamy: y=z
Pod X podstawiamy: x=z-2
((100*3/2z-2)+10*1/2z+z)=365+((100*1/2z)+(10+3/2z-2)+z+5)
150z-2+5z+z=365+50z+15z-2+z+5
150z-2+6z=365+65z-2+z+5
150z+6z-65z-2z=365-2+7
89z=370|:89
z=4 14/89
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((100*3/2z-2)+10*1/2z+z)=365+((100*1/2z)+(10+3/2z-2)+z+5)
150z-2+5z+z=365+50z+15z-2+z+5
150z-2+6z=365+65z-2+z+5
150z+6z-65z-2z=365-2+7
89z=370|:89
z=4 14/89