Rozwiąż układ równań:
2 (x-3y)-(3x-y)=3
x-3y=5
Bardzo pilne, proszę pomóżcie.
2x-6y-3x+y = 3
x = 5+3y
-x-5y = 3
-(5+3y)-5y = 3
-5-3y-5y = 3
-3y-5y = 3+5
-8y = 8 |:(-8)
y = -1
x = 5+3 |*(-1)
x = 5-3
x = 2
2x - 6y - 3x + y = 3
x - 3y = 5
-x - 5y = 3
-------------- metoda przeciwnych wsólczynników (dodajemy stronami)
- 8y = 8 / : (-8)
y= -1
x - 3(-1) = 5
x+3 = 5
x= 5 -3
x= 2
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2 (x-3y)-(3x-y)=3
x-3y=5
2x-6y-3x+y = 3
x = 5+3y
-x-5y = 3
x = 5+3y
-(5+3y)-5y = 3
x = 5+3y
-5-3y-5y = 3
x = 5+3y
-3y-5y = 3+5
x = 5+3y
-8y = 8 |:(-8)
x = 5+3y
y = -1
x = 5+3 |*(-1)
y = -1
x = 5-3
y = -1
x = 2
2 (x-3y)-(3x-y)=3
x-3y=5
2x - 6y - 3x + y = 3
x - 3y = 5
-x - 5y = 3
x - 3y = 5
-------------- metoda przeciwnych wsólczynników (dodajemy stronami)
- 8y = 8 / : (-8)
y= -1
x - 3(-1) = 5
x+3 = 5
x= 5 -3
x= 2
y = -1