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2x+y-2=0
x²-3x-2+2x-4=0
y=2-2x
x²-x-6=0
y=2-2x
≈≈
Δ=1+24=25
pierwiastek z Δ = 5
x₁=-2
x₂=3
≈≈
(x+2)(x-3)=0
y=2-2x
x=-2
y= 8
lub
x= 3
y=-4