Rozwiąż układ równań metodą podstawiania:
(x-3)(x+3)+3y-x+2=(x-2)^2+y
-2x+y=2
(x-3)(x+3)+3y-x+2=(x-2)²+y
x²-9+3y-x+2=x²-4x+4+y
x²-x²-x+4x+3y-y=4+9-2
3x+2y=11
y=2x+2
3x+2(2x+2)=11
3x+4x+4=11
7x=11-4
7x=7/:7
x=1
y=2*1+2
y=4
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(x-3)(x+3)+3y-x+2=(x-2)²+y
-2x+y=2
x²-9+3y-x+2=x²-4x+4+y
-2x+y=2
x²-x²-x+4x+3y-y=4+9-2
-2x+y=2
3x+2y=11
y=2x+2
3x+2(2x+2)=11
y=2x+2
3x+4x+4=11
y=2x+2
7x=11-4
y=2x+2
7x=7/:7
y=2x+2
x=1
y=2*1+2
x=1
y=4