rozwiąż układ równań :
a ) 5(x-y)+3=2(x+y)-7
2-3(x+y)=-5x+4y
Odpowiedz w załączniku. :)
Pozdrawiam
5(x-y)+3=2(x+y)-7
5x - 5y + 3 = 2x + 2y - 7
2 - 3x - 3y = -5x + 4y
5x - 5y - 2x - 2y = - 7 - 3
-3x - 3y + 5x - 4y = - 2
3x - 7y = -10
2x - 7y = - 2 /*(-1)
3x - 7y = - 10
-2x + 7y = 2
-----------------
x = - 8
2x - 7y = -2
-16 - 7y = -2
-7y = - 2 + 16
-7y = 14
y = - 2
x = -8
y = -2
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Odpowiedz w załączniku. :)
Pozdrawiam
5(x-y)+3=2(x+y)-7
2-3(x+y)=-5x+4y
5x - 5y + 3 = 2x + 2y - 7
2 - 3x - 3y = -5x + 4y
5x - 5y - 2x - 2y = - 7 - 3
-3x - 3y + 5x - 4y = - 2
3x - 7y = -10
2x - 7y = - 2 /*(-1)
3x - 7y = - 10
-2x + 7y = 2
-----------------
x = - 8
2x - 7y = -2
-16 - 7y = -2
-7y = - 2 + 16
-7y = 14
y = - 2
x = -8
y = -2