Question

Rozwiąż układ równań: { 2(2x-y)+3(x+3y)=42 { 5(x+3y)-8(2x-y)=-32

Answer 1

{ 2(2x-y)+3(x+3y)=42

{ 5(x+3y)-8(2x-y)=-32

 

4x-2y+3x+9y=42

5x+15y-16x+8y=-32

 

7x+7y=42/:7

-11x+23y=-32

 

x=6-y

-11(6-y)+23y=-32

-66+11y+23y=-32

34y=34

y=1

 

x=6-1

x=5

 

spr:

2(2x-y)+3(x+3y)=42

2(2*5-1)+3(5+3*1)=42

2(10-1)+3(5+3)=42

20-2+15+9=42

42=42