Rozwiąż równianie
2x^3-4x^2-8x+16=0
2x^3 - 4x^2 - 8x + 16 = 0
x^3 - 2x^2 - 4x + 8 = 0
x(x^2 - 4)-2(x^2 - 4) = 0
(x-2)(x^2-4) = 0(x-2)(x-2)(x+2) = 0
(x+2)(x-2)^2 = 0
wiec rozwiązanie to x = 2 lub x = -2
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2x^3 - 4x^2 - 8x + 16 = 0
x^3 - 2x^2 - 4x + 8 = 0
x(x^2 - 4)-2(x^2 - 4) = 0
(x-2)(x^2-4) = 0
(x-2)(x-2)(x+2) = 0
(x+2)(x-2)^2 = 0
wiec rozwiązanie to x = 2 lub x = -2