Rozwiąż równanie
x(x^4(x+3)+2)=3(x+1)
x(x^5 + 3x^4 +2) = 3x+3
x^6 + 3x^5 +2x -3x -3=0
x^6 +3x^5 -x -3 =0
x^5(x+3)-(x+3)=0
(x^5-1)(x+3)=0
x^5-1=0. u x+3=0
x=1 x=-3
odp:
x=1 u x=-3
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x(x^5 + 3x^4 +2) = 3x+3
x^6 + 3x^5 +2x -3x -3=0
x^6 +3x^5 -x -3 =0
x^5(x+3)-(x+3)=0
(x^5-1)(x+3)=0
x^5-1=0. u x+3=0
x=1 x=-3
odp:
x=1 u x=-3